4w^2+33w+23=0

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Solution for 4w^2+33w+23=0 equation:



4w^2+33w+23=0
a = 4; b = 33; c = +23;
Δ = b2-4ac
Δ = 332-4·4·23
Δ = 721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-\sqrt{721}}{2*4}=\frac{-33-\sqrt{721}}{8} $
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+\sqrt{721}}{2*4}=\frac{-33+\sqrt{721}}{8} $

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